integral of sin(x+1)

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Steps Examples

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x+y−z=0, x+2y−3z=−6, −2x+3y−4z=10

Solution

x=−4, y=14, z=10

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Solve by:

Solve by elimination

Solve by substitution

Solve by Cramer's rule

Solve by Gaussian elimination

One step at a time

[

x+y−z=0

x+2y−3z=−6

−2x+3y−4z=10

]

Subtract the equations

x+2y−3z=−6

−

x+y−z=0

y−2z=−6

[

x+y−z=0

y−2z=−6

−2x+3y−4z=10

]

Multiply x+y−z=0 by 2 : 2x+2y−2z=0

[

2x+2y−2z=0

y−2z=−6

−2x+3y−4z=10

]

Add the equations

−2x+3y−4z=10

2x+2y−2z=0

5y−6z=10

[

2x+2y−2z=0

y−2z=−6

5y−6z=10

]

Multiply y−2z=−6 by 5 : 5y−10z=−30

[

2x+2y−2z=0

5y−10z=−30

5y−6z=10

]

Subtract the equations

5y−6z=10

−

5y−10z=−30

4z=40

[

2x+2y−2z=0

5y−10z=−30

4z=40

]

Solve 4z=40 for z: z=10

For 5y−10z=−30 plug in z=10

Solve 5y−10· 10=−30 for y: y=14

For 2x+2y−2z=0 plug in y=14, z=10

Solve 2x+2· 14−2· 10=0 for x: x=−4

The solutions to the system of equations are:

x=−4, y=14, z=10

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Solve by: substitution

Solve by: Cramer's rule

Solve by: Gaussian elimination

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of sin(x+1)

Solution

Solution steps

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